Evaluate The Double Integral Where Is Bounded By And

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May 07, 2025 · 6 min read

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Evaluating Double Integrals: A Comprehensive Guide with Example
Evaluating double integrals is a fundamental concept in multivariable calculus, with applications spanning numerous fields like physics, engineering, and economics. This article provides a comprehensive guide to evaluating double integrals, focusing on a specific example: evaluating a double integral over a region bounded by specific curves. We'll explore different approaches, techniques for simplifying the integration process, and offer practical advice for tackling similar problems.
Understanding Double Integrals
A double integral extends the concept of a single integral to two dimensions. While a single integral calculates the area under a curve, a double integral calculates the volume under a surface. Mathematically, it's represented as:
∬<sub>R</sub> f(x, y) dA
where:
- f(x, y) is the function defining the surface.
- R is the region of integration in the xy-plane.
- dA represents an infinitesimally small area element within R (often expressed as dx dy or dy dx).
Our Example Problem: Region Bounded by y = x² and y = √x
Let's consider a specific problem: evaluating the double integral of the function f(x, y) = x + y over the region R bounded by the curves y = x² and y = √x.
First, we need to visualize the region R. Both curves intersect at (0, 0) and (1, 1). The curve y = √x lies above y = x² in this interval.
Visualizing the Region: It's highly recommended to sketch the region R. This visual representation will help you determine the limits of integration. Sketching y = x² (a parabola opening upwards) and y = √x (a square root function) will clearly show the enclosed region between these two curves from x = 0 to x = 1.
Choosing the Order of Integration: dx dy or dy dx?
The order of integration (dx dy or dy dx) significantly impacts the complexity of the calculation. We have two choices:
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Integrating with respect to x first (dy dx): In this approach, we’ll find the limits of x for a fixed y, then integrate with respect to y. This method can be more challenging in this specific case because finding the inverse functions might be cumbersome.
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Integrating with respect to y first (dx dy): This is generally easier for this problem. We’ll find the limits of y for a fixed x, then integrate with respect to x.
Let’s proceed with the dx dy approach, which tends to be simpler here.
Step-by-Step Evaluation: dx dy Approach
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Determine the limits of integration: For a given x value within the region R, y varies from x² to √x. Therefore, the inner integral (with respect to y) will have limits from x² to √x. The outer integral (with respect to x) will cover the range of x values from 0 to 1, based on the intersection points of the curves.
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Set up the double integral: The double integral becomes:
∫<sub>0</sub><sup>1</sup> ∫<sub>x²</sub><sup>√x</sup> (x + y) dy dx
- Evaluate the inner integral: First, we integrate (x + y) with respect to y, treating x as a constant:
∫<sub>x²</sub><sup>√x</sup> (x + y) dy = [xy + (1/2)y²]<sub>x²</sub><sup>√x</sup> = (x√x + (1/2)x) – (x³ + (1/2)x⁴)
- Evaluate the outer integral: Now we substitute the result from step 3 into the outer integral and integrate with respect to x:
∫<sub>0</sub><sup>1</sup> [(x√x + (1/2)x) – (x³ + (1/2)x⁴)] dx = ∫<sub>0</sub><sup>1</sup> (x<sup>3/2</sup> + (1/2)x – x³ – (1/2)x⁴) dx
- Perform the integration: Integrating each term with respect to x:
[ (2/5)x<sup>5/2</sup> + (1/4)x² – (1/4)x⁴ – (1/10)x⁵ ]<sub>0</sub><sup>1</sup>
- Evaluate the definite integral: Substituting the limits of integration:
(2/5) + (1/4) – (1/4) – (1/10) = 2/5 – 1/10 = 3/10
Therefore, the value of the double integral is 3/10.
Alternative Approach: dy dx
While the dx dy approach proved efficient here, let's briefly consider the alternative, integrating with respect to x first (dy dx). This will require solving for x in terms of y for both equations:
- For y = x², we have x = ±√y. Since our region is in the first quadrant, we use x = √y.
- For y = √x, we have x = y².
The limits of integration would now be:
- Outer integral (y): From 0 to 1 (the range of y values).
- Inner integral (x): From √y to y².
The double integral would become:
∫<sub>0</sub><sup>1</sup> ∫<sub>√y</sub><sup>y²</sup> (x + y) dx dy
Evaluating this integral would be more complex due to the more involved integration steps, resulting in the same final answer of 3/10.
Practical Tips and Considerations
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Sketch the region: Always begin by sketching the region of integration. This is crucial for determining the correct limits of integration.
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Choose the right order of integration: The order of integration (dx dy or dy dx) can greatly impact the complexity of the calculations. Choose the order that simplifies the integration process. Sometimes, both orders result in equally manageable computations.
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Change of variables: For more complex regions, consider using a change of variables (like polar coordinates) to simplify the integration. This is not necessary for this particular problem.
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Break down complex regions: If the region is complex and not easily described by simple inequalities, break it down into smaller, simpler regions. Evaluate the integral over each sub-region separately, and then sum the results.
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Use technology: For intricate integrals, mathematical software (like Mathematica or Maple) can assist with the calculations. However, understanding the underlying principles remains vital.
Applications of Double Integrals
Double integrals find extensive application in various disciplines:
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Calculating areas: Double integrals can calculate the area of a region in the xy-plane, even for irregularly shaped regions.
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Calculating volumes: This is the primary application discussed in this article – determining the volume of a solid under a surface.
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Physics: Used to calculate quantities like center of mass, moment of inertia, and fluid flow.
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Engineering: Applied in stress analysis, heat transfer calculations, and other engineering problems.
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Economics: Used in economic modeling for areas like resource allocation and utility maximization.
Conclusion
Evaluating double integrals can initially seem daunting, but with careful planning and a systematic approach, the process becomes manageable. Understanding the region of integration, selecting the appropriate order of integration, and carefully executing the integration steps are key to success. The example problem demonstrated a clear step-by-step process, highlighting the importance of visualization and strategic decision-making. Mastering this technique opens doors to a deeper understanding of multivariable calculus and its vast applications. Remember to always verify your solutions, perhaps through alternative methods or software, to ensure accuracy. The techniques discussed here form a solid foundation for tackling more advanced problems in multivariable calculus.
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